請(qǐng)求示例

1let wechatInfo = navigator.userAgent.match(/MicroMessenger\/([\d\.]+)/i);
2let wechatVersion = wechatInfo[1];
3?
4if (compareVersion(wechatVersion, '7.0.5') >= 0) {
5   goToWXScore();
6} else {
7   // 提示用戶升級(jí)微信客戶端版本
8   window.href = 'https://support.weixin.qq.com/cgi-bin/readtemplate?t=page/common_page__upgrade&
9   text=text005&btn_text=btn_text_0'
10}
11?
12/**
13 * 跳轉(zhuǎn)微信支付分
14 */
15function goToWXScore() {
16    wx.checkJsApi({
17        jsApiList: ['openBusinessView'], // 需要檢測(cè)的JS接口列表
18        success: function (res) {
19        // 以鍵值對(duì)的形式返回，可用的api值true，不可用為false
20        // 如：{"checkResult":{"openBusinessView":true},"errMsg":"checkJsApi:ok"}
21        if (res.checkResult.openBusinessView) {
22            wx.invoke(
23                'openBusinessView', {
24                    businessType: 'wxpayScoreDetail',
25                    queryString
26: 'mch_id=1230000109&service_id=88888888000011&out_order_no=1234323JKHDFE1243252&
27                    timestamp=1530097563&nonce_str=zyx53Nkey8o4bHpxTQvd8m7e92nG5mG2&
28                    sign_type=HMAC-SHA256&sign=029B52F67573D7E3BE74904BF9AEA'
29                },
30                
31                function (res) {
32                // 從支付分返回時(shí)會(huì)執(zhí)行這個(gè)回調(diào)函數(shù)
33                    if (parseint(res.err_code) === 0) {
34                    // 返回成功 
35                    } else {
36                    // 返回失敗
37                    }
38                });
39            }
40        }
41    });
42 }
43?
44 /**
45  * 版本號(hào)比較
46  * @param {string
47} v1 
48  * @param {string
49} v2 
50  */
51function compareVersion(v1, v2) {
52    v1 = v1.split('.')
53    v2 = v2.split('.')
54    const len = Math.max(v1.length, v2.length)
55  
56    while (v1.length < len) {
57      v1.push('0')
58    }
59    while (v2.length < len) {
60      v2.push('0')
61    }
62  
63    for (let i = 0; i < len; i++) {
64      const num1 = parseint(v1[i])
65      const num2 = parseint(v2[i])
66  
67      if (num1 > num2) {
68        return 1
69      } else if (num1 < num2) {
70        return -1
71      }
72    }
73  
74    return 0
75 }